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9x^2+17x-4=0
a = 9; b = 17; c = -4;
Δ = b2-4ac
Δ = 172-4·9·(-4)
Δ = 433
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-\sqrt{433}}{2*9}=\frac{-17-\sqrt{433}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+\sqrt{433}}{2*9}=\frac{-17+\sqrt{433}}{18} $
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